If you want to check the 59476 Patan - Mahesana Passenger (UnReserved) time table, then just enter your train number in the input box, select your train, and click on the "Get Schedule" button. By doing so, the live train timetable for the Patan - Mahesana Passenger (UnReserved) will be displayed on your device screen.
It is important to check 59476 Patan - Mahesana Passenger (UnReserved) because sometimes Indian railways change their timetable without any prior notice due to some inevitable circumstances. Therefore, it is advisable that passengers check the Patan - Mahesana Passenger (UnReserved) timetable before leaving for the railway station.
The Patan - Mahesana Passenger (UnReserved) train number is 59476.
The 59476 departs from its source station, Mahesana Jn (MSH), at 12:05.
The 59476 Patan - Mahesana Passenger (UnReserved) reaches its destination station, Mahesana Jn, at 13:10 .
The 59476 Patan - Mahesana Passenger (UnReserved) has 5 stoppages in the route, including both source and destination stations.
Patan - Mahesana Passenger (UnReserved) arrives on platform number -- at Patan (PTN) and platform number 4 at Mahesana Jn (MSH).
The 59476 Patan - Mahesana Passenger (UnReserved) runs on Sunday, Monday, Tuesday, Wednesday, Thursday, Friday and Saturday between Patan (PTN) and Mahesana Jn (MSH) stations at their respective timings.
Patan - Mahesana Passenger (UnReserved) covers a total distance of 40 km.
The available travel classes on the Patan - Mahesana Passenger (UnReserved) include General.
The 59476 takes 1h 5m to reach its destination station.
The 59476 Patan - Mahesana Passenger (UnReserved) passes by 5 major stations.